In the shortcut method, the area of the circle is obtained by multiplying the area of the bounding square by what factor?

Prepare for the CSLB Concrete C-8 License Exam with study flashcards and detailed multiple choice questions. Each question includes hints and explanations. Get exam-ready today!

Multiple Choice

In the shortcut method, the area of the circle is obtained by multiplying the area of the bounding square by what factor?

Explanation:
When you use the shortcut method, the circle sits inside a bounding square with the circle’s diameter equal to the square’s side. If the square’s area is s^2, the circle’s area is pi (s/2)^2 = (pi/4) s^2. That means the circle’s area is pi/4 times the square’s area. Since pi/4 ≈ 0.785, multiplying the square’s area by 0.785 gives the circle’s area.

When you use the shortcut method, the circle sits inside a bounding square with the circle’s diameter equal to the square’s side. If the square’s area is s^2, the circle’s area is pi (s/2)^2 = (pi/4) s^2. That means the circle’s area is pi/4 times the square’s area. Since pi/4 ≈ 0.785, multiplying the square’s area by 0.785 gives the circle’s area.

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